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NEW QUESTION: 1
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 4 kHz x 8-bit code words
B. 2 x 8 kHz x 4-bit code words
C. 2 x 4-bit code words x 8 kHz
D. 8 kHz x 8-bit code words
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400 Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz. According to Nyquist
theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps
(notice about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit
per second = 64 Kilobit per second = 64 Kbps)
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling
frequency must be greater than twice the bandwidth of the input signal in order to be able
to reconstruct the original perfectly from the sampled version."